Base | Representation |
---|---|
bin | 1011101101010… |
… | …1000001000111 |
3 | 10102101220011100 |
4 | 2323111001013 |
5 | 100032411030 |
6 | 4512311143 |
7 | 1134255066 |
oct | 273250107 |
9 | 112356140 |
10 | 49107015 |
11 | 257a0911 |
12 | 145424b3 |
13 | a234b09 |
14 | 67441dd |
15 | 44a0360 |
hex | 2ed5047 |
49107015 has 12 divisors (see below), whose sum is σ = 85118904. Its totient is φ = 26190384.
The previous prime is 49107011. The next prime is 49107043. The reversal of 49107015 is 51070194.
49107015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 49107015 - 22 = 49107011 is a prime.
It is a super-2 number, since 2×491070152 = 4822997844420450, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 49107015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49107011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 545589 + ... + 545678.
It is an arithmetic number, because the mean of its divisors is an integer number (7093242).
Almost surely, 249107015 is an apocalyptic number.
49107015 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
49107015 is a deficient number, since it is larger than the sum of its proper divisors (36011889).
49107015 is a wasteful number, since it uses less digits than its factorization.
49107015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1091278 (or 1091275 counting only the distinct ones).
The product of its (nonzero) digits is 1260, while the sum is 27.
The square root of 49107015 is about 7007.6397595767. The cubic root of 49107015 is about 366.1967722699.
It can be divided in two parts, 4 and 9107015, that added together give a palindrome (9107019).
The spelling of 49107015 in words is "forty-nine million, one hundred seven thousand, fifteen".
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