Base | Representation |
---|---|
bin | 10010011100011110011111 |
3 | 100002122200122 |
4 | 102130132133 |
5 | 2214211411 |
6 | 251345155 |
7 | 56045612 |
oct | 22343637 |
9 | 10078618 |
10 | 4835231 |
11 | 2802865 |
12 | 17521bb |
13 | 1003aab |
14 | 8dc179 |
15 | 6579db |
hex | 49c79f |
4835231 has 2 divisors, whose sum is σ = 4835232. Its totient is φ = 4835230.
The previous prime is 4835213. The next prime is 4835249. The reversal of 4835231 is 1325384.
Together with previous prime (4835213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (4835213) and next prime (4835249).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4835231 is a prime.
It is a super-2 number, since 2×48352312 = 46758917646722, which contains 22 as substring.
It is a Chen prime.
It is equal to p337724 and since 4835231 and 337724 have the same sum of digits, it is a Honaker prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4835231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4835251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2417615 + 2417616.
It is an arithmetic number, because the mean of its divisors is an integer number (2417616).
Almost surely, 24835231 is an apocalyptic number.
4835231 is a deficient number, since it is larger than the sum of its proper divisors (1).
4835231 is an equidigital number, since it uses as much as digits as its factorization.
4835231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2880, while the sum is 26.
The square root of 4835231 is about 2198.9158692410. The cubic root of 4835231 is about 169.0982354306.
The spelling of 4835231 in words is "four million, eight hundred thirty-five thousand, two hundred thirty-one".
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