Base | Representation |
---|---|
bin | 1100100011001101… |
… | …1001000010101001 |
3 | 22200210012121201211 |
4 | 3020303121002221 |
5 | 23344420240423 |
6 | 1314143313121 |
7 | 146325206644 |
oct | 31063310251 |
9 | 8623177654 |
10 | 3368915113 |
11 | 1479734873 |
12 | 7a02ab7a1 |
13 | 418c610c5 |
14 | 23d5d8a5b |
15 | 14ab6710d |
hex | c8cd90a9 |
3368915113 has 2 divisors, whose sum is σ = 3368915114. Its totient is φ = 3368915112.
The previous prime is 3368915107. The next prime is 3368915149. The reversal of 3368915113 is 3115198633.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3334716009 + 34199104 = 57747^2 + 5848^2 .
It is an emirp because it is prime and its reverse (3115198633) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3368915113 is a prime.
It is a super-2 number, since 2×33689151132 = 22699178077199605538, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3368915813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1684457556 + 1684457557.
It is an arithmetic number, because the mean of its divisors is an integer number (1684457557).
Almost surely, 23368915113 is an apocalyptic number.
It is an amenable number.
3368915113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3368915113 is an equidigital number, since it uses as much as digits as its factorization.
3368915113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58320, while the sum is 40.
The square root of 3368915113 is about 58042.3561978664. The cubic root of 3368915113 is about 1499.0979929568.
The spelling of 3368915113 in words is "three billion, three hundred sixty-eight million, nine hundred fifteen thousand, one hundred thirteen".
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