Base | Representation |
---|---|
bin | 1100011100011100… |
… | …1001011100101011 |
3 | 22121210210222222021 |
4 | 3013013021130223 |
5 | 23320134232231 |
6 | 1311251205311 |
7 | 145532055526 |
oct | 30707113453 |
9 | 8553728867 |
10 | 3340539691 |
11 | 1464713a05 |
12 | 7928a6837 |
13 | 413107708 |
14 | 23992dbbd |
15 | 14840e811 |
hex | c71c972b |
3340539691 has 2 divisors, whose sum is σ = 3340539692. Its totient is φ = 3340539690.
The previous prime is 3340539689. The next prime is 3340539721. The reversal of 3340539691 is 1969350433.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3340539691 - 21 = 3340539689 is a prime.
It is a super-3 number, since 3×33405396913 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 3340539689, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3340539611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670269845 + 1670269846.
It is an arithmetic number, because the mean of its divisors is an integer number (1670269846).
Almost surely, 23340539691 is an apocalyptic number.
3340539691 is a deficient number, since it is larger than the sum of its proper divisors (1).
3340539691 is an equidigital number, since it uses as much as digits as its factorization.
3340539691 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 262440, while the sum is 43.
The square root of 3340539691 is about 57797.4021128978. The cubic root of 3340539691 is about 1494.8772942096.
The spelling of 3340539691 in words is "three billion, three hundred forty million, five hundred thirty-nine thousand, six hundred ninety-one".
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