3331221433 has 4 divisors (see below), whose sum is σ = 3365564020. Its totient is φ = 3296878848.

The previous prime is 3331221431. The next prime is 3331221449. The reversal of 3331221433 is 3341221333.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 457403769 + 2873817664 = 21387^2 + 53608^2 .

It is a cyclic number.

It is not a de Polignac number, because 3331221433 - 2¹ = 3331221431 is a prime.

It is a super-2 number, since 2×3331221433² = 22194072471357146978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3331221398 and 3331221407.

It is not an unprimeable number, because it can be changed into a prime (3331221431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17171148 + ... + 17171341.

It is an arithmetic number, because the mean of its divisors is an integer number (841391005).

Almost surely, 2^3331221433 is an apocalyptic number.

It is an amenable number.

3331221433 is a deficient number, since it is larger than the sum of its proper divisors (34342587).

3331221433 is an equidigital number, since it uses as much as digits as its factorization.

3331221433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34342586.

The product of its digits is 3888, while the sum is 25.

The square root of 3331221433 is about 57716.7344277204. The cubic root of 3331221433 is about 1493.4860395309.

Adding to 3331221433 its reverse (3341221333), we get a palindrome (6672442766).

It can be divided in two parts, 33312 and 21433, that added together give a palindrome (54745).

The spelling of 3331221433 in words is "three billion, three hundred thirty-one million, two hundred twenty-one thousand, four hundred thirty-three".