3311341133 has 4 divisors (see below), whose sum is σ = 3425525340. Its totient is φ = 3197156928.

The previous prime is 3311341093. The next prime is 3311341139. The reversal of 3311341133 is 3311431133.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1670929129 + 1640412004 = 40877^2 + 40502^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3311341133 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3311341099 and 3311341108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3311341139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57092060 + ... + 57092117.

It is an arithmetic number, because the mean of its divisors is an integer number (856381335).

Almost surely, 2^3311341133 is an apocalyptic number.

It is an amenable number.

3311341133 is a deficient number, since it is larger than the sum of its proper divisors (114184207).

3311341133 is a wasteful number, since it uses less digits than its factorization.

3311341133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114184206.

The product of its digits is 972, while the sum is 23.

The square root of 3311341133 is about 57544.2536922671. The cubic root of 3311341133 is about 1490.5091323474.

Adding to 3311341133 its reverse (3311431133), we get a palindrome (6622772266).

Subtracting 3311341133 from its reverse (3311431133), we obtain a square (90000 = 300²).

The spelling of 3311341133 in words is "three billion, three hundred eleven million, three hundred forty-one thousand, one hundred thirty-three".