Base | Representation |
---|---|
bin | 1100000010010111… |
… | …0010000110100111 |
3 | 22100011221102010100 |
4 | 3000211302012213 |
5 | 23104132130043 |
6 | 1252342155143 |
7 | 143033103102 |
oct | 30045620647 |
9 | 8304842110 |
10 | 3231130023 |
11 | 14089858a0 |
12 | 762122ab3 |
13 | 3c654ac74 |
14 | 2291ad739 |
15 | 13d9ebcd3 |
hex | c09721a7 |
3231130023 has 48 divisors (see below), whose sum is σ = 5157075456. Its totient is φ = 1933182720.
The previous prime is 3231130013. The next prime is 3231130061. The reversal of 3231130023 is 3200311323.
3231130023 is a `hidden beast` number, since 32 + 311 + 300 + 23 = 666.
It is not a de Polignac number, because 3231130023 - 218 = 3230867879 is a prime.
It is a super-3 number, since 3×32311300233 (a number of 30 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3231129978 and 3231130005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3231130003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4105236 + ... + 4106022.
It is an arithmetic number, because the mean of its divisors is an integer number (107439072).
Almost surely, 23231130023 is an apocalyptic number.
3231130023 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3231130023 is a deficient number, since it is larger than the sum of its proper divisors (1925945433).
3231130023 is a wasteful number, since it uses less digits than its factorization.
3231130023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1284 (or 1281 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
The square root of 3231130023 is about 56843.0296782288. The cubic root of 3231130023 is about 1478.3756867571.
Adding to 3231130023 its reverse (3200311323), we get a palindrome (6431441346).
It can be divided in two parts, 32311300 and 23, that added together give a palindrome (32311323).
The spelling of 3231130023 in words is "three billion, two hundred thirty-one million, one hundred thirty thousand, twenty-three".
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