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322013113 is a prime number
BaseRepresentation
bin10011001100011…
…000011110111001
3211102220221221121
4103030120132321
51124413404423
651541505241
710660031512
oct2314303671
9742827847
10322013113
1115584a244
128ba12221
1351937606
1430aa3a09
151d40b45d
hex133187b9

322013113 has 2 divisors, whose sum is σ = 322013114. Its totient is φ = 322013112.

The previous prime is 322013077. The next prime is 322013119. The reversal of 322013113 is 311310223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 318372649 + 3640464 = 17843^2 + 1908^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-322013113 is a prime.

It is a super-3 number, since 3×3220131133 (a number of 27 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (322013119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161006556 + 161006557.

It is an arithmetic number, because the mean of its divisors is an integer number (161006557).

Almost surely, 2322013113 is an apocalyptic number.

It is an amenable number.

322013113 is a deficient number, since it is larger than the sum of its proper divisors (1).

322013113 is an equidigital number, since it uses as much as digits as its factorization.

322013113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 322013113 is about 17944.7238206666. The cubic root of 322013113 is about 685.4217042110.

Adding to 322013113 its reverse (311310223), we get a palindrome (633323336).

The spelling of 322013113 in words is "three hundred twenty-two million, thirteen thousand, one hundred thirteen".