Base | Representation |
---|---|
bin | 10011000100100… |
… | …000110011100111 |
3 | 211022001010222001 |
4 | 103010200303213 |
5 | 1123401400210 |
6 | 51425350131 |
7 | 10633346665 |
oct | 2304406347 |
9 | 738033861 |
10 | 319950055 |
11 | 154670237 |
12 | 8b198347 |
13 | 51394579 |
14 | 306c7c35 |
15 | 1d15003a |
hex | 13120ce7 |
319950055 has 4 divisors (see below), whose sum is σ = 383940072. Its totient is φ = 255960040.
The previous prime is 319950053. The next prime is 319950067. The reversal of 319950055 is 550059913.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 319950055 - 21 = 319950053 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 319949996 and 319950023.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (319950053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31995001 + ... + 31995010.
It is an arithmetic number, because the mean of its divisors is an integer number (95985018).
Almost surely, 2319950055 is an apocalyptic number.
319950055 is a deficient number, since it is larger than the sum of its proper divisors (63990017).
319950055 is an equidigital number, since it uses as much as digits as its factorization.
319950055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63990016.
The product of its (nonzero) digits is 30375, while the sum is 37.
The square root of 319950055 is about 17887.1477603334. The cubic root of 319950055 is about 683.9547915072.
The spelling of 319950055 in words is "three hundred nineteen million, nine hundred fifty thousand, fifty-five".
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