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315134023 is a prime number
BaseRepresentation
bin10010110010001…
…001000001000111
3210221222110121111
4102302021001013
51121133242043
651134225451
710544411041
oct2262110107
9727873544
10315134023
11151980946
1289655287
1350399449
142dbd2a91
151c9ed09d
hex12c89047

315134023 has 2 divisors, whose sum is σ = 315134024. Its totient is φ = 315134022.

The previous prime is 315134009. The next prime is 315134033. The reversal of 315134023 is 320431513.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 315134023 - 213 = 315125831 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 315133985 and 315134003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315134033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157567011 + 157567012.

It is an arithmetic number, because the mean of its divisors is an integer number (157567012).

Almost surely, 2315134023 is an apocalyptic number.

315134023 is a deficient number, since it is larger than the sum of its proper divisors (1).

315134023 is an equidigital number, since it uses as much as digits as its factorization.

315134023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 315134023 is about 17752.0146180652. The cubic root of 315134023 is about 680.5056957793.

Adding to 315134023 its reverse (320431513), we get a palindrome (635565536).

The spelling of 315134023 in words is "three hundred fifteen million, one hundred thirty-four thousand, twenty-three".