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3144212143 = 5051622493
BaseRepresentation
bin1011101101101000…
…1101111010101111
322010010101112012121
42323122031322233
522414404242033
61235555213411
7140626235152
oct27332157257
98103345177
103144212143
11137390a136
12738ba7267
133b1537b77
1421b825c99
1513607d62d
hexbb68deaf

3144212143 has 4 divisors (see below), whose sum is σ = 3144839688. Its totient is φ = 3143584600.

The previous prime is 3144212119. The next prime is 3144212173. The reversal of 3144212143 is 3412124413.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3412124413 = 16963201151.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3144212143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3144212173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306196 + ... + 316297.

It is an arithmetic number, because the mean of its divisors is an integer number (786209922).

Almost surely, 23144212143 is an apocalyptic number.

3144212143 is a deficient number, since it is larger than the sum of its proper divisors (627545).

3144212143 is an equidigital number, since it uses as much as digits as its factorization.

3144212143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 627544.

The product of its digits is 2304, while the sum is 25.

The square root of 3144212143 is about 56073.2747661486. The cubic root of 3144212143 is about 1464.9988379588.

Adding to 3144212143 its reverse (3412124413), we get a palindrome (6556336556).

The spelling of 3144212143 in words is "three billion, one hundred forty-four million, two hundred twelve thousand, one hundred forty-three".

Divisors: 1 5051 622493 3144212143