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3144012503 = 35358715173
BaseRepresentation
bin1011101101100101…
…1101001011010111
322010010000101100112
42323121131023113
522414331400003
61235551033235
7140624444132
oct27331351327
98103011315
103144012503
111373793145
12738b0b81b
133b1498038
1421b7b3219
1513603e3d8
hexbb65d2d7

3144012503 has 8 divisors (see below), whose sum is σ = 3158498448. Its totient is φ = 3129558784.

The previous prime is 3144012499. The next prime is 3144012539. The reversal of 3144012503 is 3052104413.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3144012503 - 22 = 3144012499 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3144012563) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199625 + ... + 214797.

It is an arithmetic number, because the mean of its divisors is an integer number (394812306).

Almost surely, 23144012503 is an apocalyptic number.

3144012503 is a deficient number, since it is larger than the sum of its proper divisors (14485945).

3144012503 is a wasteful number, since it uses less digits than its factorization.

3144012503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16113.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3144012503 is about 56071.4945672041. The cubic root of 3144012503 is about 1464.9678308739.

Adding to 3144012503 its reverse (3052104413), we get a palindrome (6196116916).

The spelling of 3144012503 in words is "three billion, one hundred forty-four million, twelve thousand, five hundred three".

Divisors: 1 353 587 15173 207211 5356069 8906551 3144012503