Base | Representation |
---|---|
bin | 1011100111111001… |
… | …0101000001111111 |
3 | 22001110001201112022 |
4 | 2321332111001333 |
5 | 22342222432111 |
6 | 1233335030355 |
7 | 140214421343 |
oct | 27176250177 |
9 | 8043051468 |
10 | 3120124031 |
11 | 1361257402 |
12 | 730b0b3bb |
13 | 3a9552a4b |
14 | 218555623 |
15 | 133dc12db |
hex | b9f9507f |
3120124031 has 2 divisors, whose sum is σ = 3120124032. Its totient is φ = 3120124030.
The previous prime is 3120124013. The next prime is 3120124037. The reversal of 3120124031 is 1304210213.
Together with previous prime (3120124013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (1304210213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3120124031 - 226 = 3053015167 is a prime.
It is a super-2 number, since 2×31201240312 = 19470347937647377922, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3120124037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560062015 + 1560062016.
It is an arithmetic number, because the mean of its divisors is an integer number (1560062016).
Almost surely, 23120124031 is an apocalyptic number.
3120124031 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120124031 is an equidigital number, since it uses as much as digits as its factorization.
3120124031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 3120124031 is about 55858.0704195911. The cubic root of 3120124031 is about 1461.2480775537.
Adding to 3120124031 its reverse (1304210213), we get a palindrome (4424334244).
The spelling of 3120124031 in words is "three billion, one hundred twenty million, one hundred twenty-four thousand, thirty-one".
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