3113041015 has 8 divisors (see below), whose sum is σ = 4269313440. Its totient is φ = 2134656672.

The previous prime is 3113040979. The next prime is 3113041051. The reversal of 3113041015 is 5101403113.

It is an interprime number because it is at equal distance from previous prime (3113040979) and next prime (3113041051).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3113041015 - 2¹⁵ = 3113008247 is a prime.

It is a super-2 number, since 2×3113041015² = 19382048722144460450, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3113040983 and 3113041001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44471980 + ... + 44472049.

It is an arithmetic number, because the mean of its divisors is an integer number (533664180).

Almost surely, 2^3113041015 is an apocalyptic number.

3113041015 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

3113041015 is a deficient number, since it is larger than the sum of its proper divisors (1156272425).

3113041015 is an equidigital number, since it uses as much as digits as its factorization.

3113041015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88944041.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 3113041015 is about 55794.6324927407. The cubic root of 3113041015 is about 1460.1415098654.

Adding to 3113041015 its reverse (5101403113), we get a palindrome (8214444128).

The spelling of 3113041015 in words is "three billion, one hundred thirteen million, forty-one thousand, fifteen".