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3102113 = 7443159
BaseRepresentation
bin1011110101010110100001
312211121022002
423311112201
51243231423
6150253345
735240030
oct13652641
95747262
103102113
111829733
121057255
13847c91
145aa717
15414228
hex2f55a1

3102113 has 4 divisors (see below), whose sum is σ = 3545280. Its totient is φ = 2658948.

The previous prime is 3102107. The next prime is 3102131. The reversal of 3102113 is 3112013.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112013 = 25712109.

It is a cyclic number.

It is not a de Polignac number, because 3102113 - 24 = 3102097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3102094 and 3102103.

It is not an unprimeable number, because it can be changed into a prime (3102103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221573 + ... + 221586.

It is an arithmetic number, because the mean of its divisors is an integer number (886320).

Almost surely, 23102113 is an apocalyptic number.

It is an amenable number.

3102113 is a deficient number, since it is larger than the sum of its proper divisors (443167).

3102113 is an equidigital number, since it uses as much as digits as its factorization.

3102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443166.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 3102113 is about 1761.2816356279. The cubic root of 3102113 is about 145.8430947117.

Adding to 3102113 its reverse (3112013), we get a palindrome (6214126).

The spelling of 3102113 in words is "three million, one hundred two thousand, one hundred thirteen".

Divisors: 1 7 443159 3102113