3100121113 has 4 divisors (see below), whose sum is σ = 3108215808. Its totient is φ = 3092026420.

The previous prime is 3100121047. The next prime is 3100121119. The reversal of 3100121113 is 3111210013.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3100121113 - 2⁹ = 3100120601 is a prime.

It is a super-2 number, since 2×3100121113² = 19221501830536717538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3100121093 and 3100121102.

It is not an unprimeable number, because it can be changed into a prime (3100121119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4046773 + ... + 4047538.

It is an arithmetic number, because the mean of its divisors is an integer number (777053952).

Almost surely, 2^3100121113 is an apocalyptic number.

It is an amenable number.

3100121113 is a deficient number, since it is larger than the sum of its proper divisors (8094695).

3100121113 is an equidigital number, since it uses as much as digits as its factorization.

3100121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8094694.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 3100121113 is about 55678.7312445246. The cubic root of 3100121113 is about 1458.1187242712.

Adding to 3100121113 its reverse (3111210013), we get a palindrome (6211331126).

Subtracting 3100121113 from its reverse (3111210013), we obtain a square (11088900 = 3330²).

The spelling of 3100121113 in words is "three billion, one hundred million, one hundred twenty-one thousand, one hundred thirteen".