36145433 has 4 divisors (see below), whose sum is σ = 36158208. Its totient is φ = 36132660.

The previous prime is 36145427. The next prime is 36145441. The reversal of 36145433 is 33454163.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 33454163 = 353 ⋅94771.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-36145433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 36145396 and 36145405.

It is not an unprimeable number, because it can be changed into a prime (36145033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41 + ... + 8502.

It is an arithmetic number, because the mean of its divisors is an integer number (9039552).

Almost surely, 2^36145433 is an apocalyptic number.

It is an amenable number.

36145433 is a deficient number, since it is larger than the sum of its proper divisors (12775).

36145433 is an equidigital number, since it uses as much as digits as its factorization.

36145433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12774.

The product of its digits is 12960, while the sum is 29.

The square root of 36145433 is about 6012.1072013064. The cubic root of 36145433 is about 330.6367656139.

Adding to 36145433 its reverse (33454163), we get a palindrome (69599596).

The spelling of 36145433 in words is "thirty-six million, one hundred forty-five thousand, four hundred thirty-three".