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3555243149 is a prime number
BaseRepresentation
bin1101001111101000…
…1011010010001101
3100011202211001202012
43103322023102031
524240120240044
61344441111005
7154050032243
oct32372132215
910152731665
103555243149
111564929887
12832788465
1344873c393
1425a25c793
1515c1c059e
hexd3e8b48d

3555243149 has 2 divisors, whose sum is σ = 3555243150. Its totient is φ = 3555243148.

The previous prime is 3555243103. The next prime is 3555243151. The reversal of 3555243149 is 9413425553.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2270522500 + 1284720649 = 47650^2 + 35843^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3555243149 is a prime.

It is a super-2 number, since 2×35552431492 = 25279507697022872402, which contains 22 as substring.

Together with 3555243151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3555243199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1777621574 + 1777621575.

It is an arithmetic number, because the mean of its divisors is an integer number (1777621575).

Almost surely, 23555243149 is an apocalyptic number.

It is an amenable number.

3555243149 is a deficient number, since it is larger than the sum of its proper divisors (1).

3555243149 is an equidigital number, since it uses as much as digits as its factorization.

3555243149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 324000, while the sum is 41.

The square root of 3555243149 is about 59625.8597338437. The cubic root of 3555243149 is about 1526.2409533993.

The spelling of 3555243149 in words is "three billion, five hundred fifty-five million, two hundred forty-three thousand, one hundred forty-nine".