3552064433 has 4 divisors (see below), whose sum is σ = 3627640320. Its totient is φ = 3476488548.

The previous prime is 3552064387. The next prime is 3552064471. The reversal of 3552064433 is 3344602553.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3344602553 = 149 ⋅22446997.

It is a cyclic number.

It is not a de Polignac number, because 3552064433 - 2¹⁰ = 3552063409 is a prime.

It is a super-2 number, since 2×3552064433² = 25234323472367222978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3552064393 and 3552064402.

It is not an unprimeable number, because it can be changed into a prime (3552064933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37787873 + ... + 37787966.

It is an arithmetic number, because the mean of its divisors is an integer number (906910080).

Almost surely, 2^3552064433 is an apocalyptic number.

It is an amenable number.

3552064433 is a deficient number, since it is larger than the sum of its proper divisors (75575887).

3552064433 is an equidigital number, since it uses as much as digits as its factorization.

3552064433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75575886.

The product of its (nonzero) digits is 129600, while the sum is 35.

The square root of 3552064433 is about 59599.1982580303. The cubic root of 3552064433 is about 1525.7859509380.

Adding to 3552064433 its reverse (3344602553), we get a palindrome (6896666986).

The spelling of 3552064433 in words is "three billion, five hundred fifty-two million, sixty-four thousand, four hundred thirty-three".