35442131 has 2 divisors, whose sum is σ = 35442132. Its totient is φ = 35442130.

The previous prime is 35442097. The next prime is 35442133. The reversal of 35442131 is 13124453.

35442131 is nontrivially palindromic in base 12.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-35442131 is a prime.

It is a super-2 number, since 2×35442131² = 2512289299642322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 35442133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 35442097 and 35442106.

It is not a weakly prime, because it can be changed into another prime (35442133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17721065 + 17721066.

It is an arithmetic number, because the mean of its divisors is an integer number (17721066).

Almost surely, 2^35442131 is an apocalyptic number.

35442131 is a deficient number, since it is larger than the sum of its proper divisors (1).

35442131 is an equidigital number, since it uses as much as digits as its factorization.

35442131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 23.

The square root of 35442131 is about 5953.3294046273. The cubic root of 35442131 is about 328.4782428424.

Adding to 35442131 its reverse (13124453), we get a palindrome (48566584).

The spelling of 35442131 in words is "thirty-five million, four hundred forty-two thousand, one hundred thirty-one".