35401 has 2 divisors, whose sum is σ = 35402. Its totient is φ = 35400.

The previous prime is 35393. The next prime is 35407. The reversal of 35401 is 10453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25600 + 9801 = 160^2 + 99^2 .

It is an emirp because it is prime and its reverse (10453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35401 - 2³ = 35393 is a prime.

It is a Chen prime.

It is a nialpdrome in base 15.

It is not a weakly prime, because it can be changed into another prime (35407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17700 + 17701.

It is an arithmetic number, because the mean of its divisors is an integer number (17701).

2³⁵⁴⁰¹ is an apocalyptic number.

It is an amenable number.

35401 is a deficient number, since it is larger than the sum of its proper divisors (1).

35401 is an equidigital number, since it uses as much as digits as its factorization.

35401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 35401 is about 188.1515346735. The cubic root of 35401 is about 32.8351126065.

Adding to 35401 its reverse (10453), we get a palindrome (45854).

The spelling of 35401 in words is "thirty-five thousand, four hundred one".