Base | Representation |
---|---|
bin | 1000011010000… |
… | …1011000101001 |
3 | 2110100121011121 |
4 | 2012201120221 |
5 | 33011422131 |
6 | 3255455241 |
7 | 605511421 |
oct | 206413051 |
9 | 73317147 |
10 | 35264041 |
11 | 189a643a |
12 | b987521 |
13 | 73c8cc7 |
14 | 497d481 |
15 | 3168911 |
hex | 21a1629 |
35264041 has 2 divisors, whose sum is σ = 35264042. Its totient is φ = 35264040.
The previous prime is 35263993. The next prime is 35264063. The reversal of 35264041 is 14046253.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26998416 + 8265625 = 5196^2 + 2875^2 .
It is a cyclic number.
It is not a de Polignac number, because 35264041 - 217 = 35132969 is a prime.
It is a super-3 number, since 3×352640413 (a number of 24 digits) contains 333 as substring.
It is a nialpdrome in base 12.
It is a junction number, because it is equal to n+sod(n) for n = 35263997 and 35264015.
It is not a weakly prime, because it can be changed into another prime (35264941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17632020 + 17632021.
It is an arithmetic number, because the mean of its divisors is an integer number (17632021).
Almost surely, 235264041 is an apocalyptic number.
It is an amenable number.
35264041 is a deficient number, since it is larger than the sum of its proper divisors (1).
35264041 is an equidigital number, since it uses as much as digits as its factorization.
35264041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 35264041 is about 5938.3533913030. The cubic root of 35264041 is about 327.9271384113.
The spelling of 35264041 in words is "thirty-five million, two hundred sixty-four thousand, forty-one".
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