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2050240035 = 35178040157
BaseRepresentation
bin111101000110100…
…0010111000100011
312021212212222121010
41322031002320203
513144330140120
6535235432003
7101543516124
oct17215027043
95255788533
102050240035
11962341758
12492755603
132689b7aac
1415641604b
15beed87e0
hex7a342e23

2050240035 has 16 divisors (see below), whose sum is σ = 3473348256. Its totient is φ = 1029139968.

The previous prime is 2050240013. The next prime is 2050240061. The reversal of 2050240035 is 5300420502.

It is not a de Polignac number, because 2050240035 - 227 = 1916022307 is a prime.

It is a super-2 number, since 2×20502400352 = 8406968402233602450, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2050239993 and 2050240020.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4019824 + ... + 4020333.

It is an arithmetic number, because the mean of its divisors is an integer number (217084266).

Almost surely, 22050240035 is an apocalyptic number.

2050240035 is a deficient number, since it is larger than the sum of its proper divisors (1423108221).

2050240035 is a wasteful number, since it uses less digits than its factorization.

2050240035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8040182.

The product of its (nonzero) digits is 1200, while the sum is 21.

The square root of 2050240035 is about 45279.5763562337. The cubic root of 2050240035 is about 1270.3836720804.

Adding to 2050240035 its reverse (5300420502), we get a palindrome (7350660537).

The spelling of 2050240035 in words is "two billion, fifty million, two hundred forty thousand, thirty-five".

Divisors: 1 3 5 15 17 51 85 255 8040157 24120471 40200785 120602355 136682669 410048007 683413345 2050240035