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2030042013 = 33891739539
BaseRepresentation
bin111100011111111…
…1111101110011101
312020110212211010020
41320333333232131
513124142321023
6533234502353
7101210033556
oct17077775635
95213784106
102030042013
119519a667a
12487a349b9
132647654bc
1415387932d
15bd348de3
hex78fffb9d

2030042013 has 8 divisors (see below), whose sum is σ = 2713682400. Its totient is φ = 1349881488.

The previous prime is 2030042009. The next prime is 2030042039. The reversal of 2030042013 is 3102400302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2030042013 - 22 = 2030042009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2030041983 and 2030042001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2030040013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 868603 + ... + 870936.

It is an arithmetic number, because the mean of its divisors is an integer number (339210300).

Almost surely, 22030042013 is an apocalyptic number.

It is an amenable number.

2030042013 is a deficient number, since it is larger than the sum of its proper divisors (683640387).

2030042013 is a wasteful number, since it uses less digits than its factorization.

2030042013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1739931.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 2030042013 is about 45055.9875377291. The cubic root of 2030042013 is about 1266.1981519888.

Adding to 2030042013 its reverse (3102400302), we get a palindrome (5132442315).

The spelling of 2030042013 in words is "two billion, thirty million, forty-two thousand, thirteen".

Divisors: 1 3 389 1167 1739539 5218617 676680671 2030042013