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2030425115 = 5596882797
BaseRepresentation
bin111100100000101…
…1101010000011011
312020111121021122012
41321001131100123
513124242100430
6533251020135
7101213220515
oct17101352033
95214537565
102030425115
11952138494
12487b9a64b
1326486a9a4
14153938bb5
15bd3c2695
hex7905d41b

2030425115 has 8 divisors (see below), whose sum is σ = 2477807280. Its totient is φ = 1596808672.

The previous prime is 2030425097. The next prime is 2030425123. The reversal of 2030425115 is 5115240302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2030425115 is a prime.

It is a super-2 number, since 2×20304251152 = 8245252295245526450, which contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3441104 + ... + 3441693.

It is an arithmetic number, because the mean of its divisors is an integer number (309725910).

Almost surely, 22030425115 is an apocalyptic number.

2030425115 is a deficient number, since it is larger than the sum of its proper divisors (447382165).

2030425115 is an equidigital number, since it uses as much as digits as its factorization.

2030425115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6882861.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 2030425115 is about 45060.2387366068. The cubic root of 2030425115 is about 1266.2777977186.

Adding to 2030425115 its reverse (5115240302), we get a palindrome (7145665417).

The spelling of 2030425115 in words is "two billion, thirty million, four hundred twenty-five thousand, one hundred fifteen".

Divisors: 1 5 59 295 6882797 34413985 406085023 2030425115