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2015450231 is a prime number
BaseRepresentation
bin111100000100001…
…0101010001110111
312012110102110221212
41320020111101313
513111423401411
6531554032035
7100642021124
oct17010252167
95173373855
102015450231
1194473a653
12482b7861b
13261726902
1415195b74b
15bbe1568b
hex78215477

2015450231 has 2 divisors, whose sum is σ = 2015450232. Its totient is φ = 2015450230.

The previous prime is 2015450219. The next prime is 2015450237. The reversal of 2015450231 is 1320545102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2015450231 - 210 = 2015449207 is a prime.

It is a super-2 number, since 2×20154502312 = 8124079267275906722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2015450197 and 2015450206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2015450237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007725115 + 1007725116.

It is an arithmetic number, because the mean of its divisors is an integer number (1007725116).

Almost surely, 22015450231 is an apocalyptic number.

2015450231 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015450231 is an equidigital number, since it uses as much as digits as its factorization.

2015450231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 2015450231 is about 44893.7660594430. The cubic root of 2015450231 is about 1263.1570764623.

Adding to 2015450231 its reverse (1320545102), we get a palindrome (3335995333).

The spelling of 2015450231 in words is "two billion, fifteen million, four hundred fifty thousand, two hundred thirty-one".