Base | Representation |
---|---|
bin | 100110011010… |
… | …1000001110111 |
3 | 1101220020002112 |
4 | 1030311001313 |
5 | 20123441101 |
6 | 1555401235 |
7 | 333121433 |
oct | 114650167 |
9 | 41806075 |
10 | 20140151 |
11 | 10406659 |
12 | 68b321b |
13 | 4232165 |
14 | 29639c3 |
15 | 1b7c6bb |
hex | 1335077 |
20140151 has 2 divisors, whose sum is σ = 20140152. Its totient is φ = 20140150.
The previous prime is 20140097. The next prime is 20140163. The reversal of 20140151 is 15104102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20140151 - 210 = 20139127 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20140451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10070075 + 10070076.
It is an arithmetic number, because the mean of its divisors is an integer number (10070076).
Almost surely, 220140151 is an apocalyptic number.
20140151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20140151 is an equidigital number, since it uses as much as digits as its factorization.
20140151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 14.
The square root of 20140151 is about 4487.7779579654. Note that the first 3 decimals coincide. The cubic root of 20140151 is about 272.0743335982.
Adding to 20140151 its reverse (15104102), we get a palindrome (35244253).
The spelling of 20140151 in words is "twenty million, one hundred forty thousand, one hundred fifty-one".
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