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200220113 is a prime number
BaseRepresentation
bin10111110111100…
…01110111010001
3111221202020100202
423323301313101
5402224020423
631511224545
74650562052
oct1373616721
9457666322
10200220113
11a3023375
1257078155
1332633552
141c83c729
151289e728
hexbef1dd1

200220113 has 2 divisors, whose sum is σ = 200220114. Its totient is φ = 200220112.

The previous prime is 200220109. The next prime is 200220121. The reversal of 200220113 is 311022002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129777664 + 70442449 = 11392^2 + 8393^2 .

It is a cyclic number.

It is not a de Polignac number, because 200220113 - 22 = 200220109 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 200220094 and 200220103.

It is not a weakly prime, because it can be changed into another prime (200220173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100110056 + 100110057.

It is an arithmetic number, because the mean of its divisors is an integer number (100110057).

Almost surely, 2200220113 is an apocalyptic number.

It is an amenable number.

200220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200220113 is an equidigital number, since it uses as much as digits as its factorization.

200220113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 200220113 is about 14149.9156534589. The cubic root of 200220113 is about 585.0180070918.

Adding to 200220113 its reverse (311022002), we get a palindrome (511242115).

The spelling of 200220113 in words is "two hundred million, two hundred twenty thousand, one hundred thirteen".