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2002112011 = 5873410753
BaseRepresentation
bin111011101010101…
…1100111000001011
312011112022211100201
41313111130320023
513100020041021
6530400113031
7100420446154
oct16725347013
95145284321
102002112011
1193815a429
1247a605777
1325ba36783
1414dc8892b
15bab7d591
hex7755ce0b

2002112011 has 4 divisors (see below), whose sum is σ = 2005523352. Its totient is φ = 1998700672.

The previous prime is 2002112003. The next prime is 2002112017. The reversal of 2002112011 is 1102112002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1102112002 = 2551056001.

It is a cyclic number.

It is not a de Polignac number, because 2002112011 - 23 = 2002112003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002112017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1704790 + ... + 1705963.

It is an arithmetic number, because the mean of its divisors is an integer number (501380838).

Almost surely, 22002112011 is an apocalyptic number.

2002112011 is a deficient number, since it is larger than the sum of its proper divisors (3411341).

2002112011 is an equidigital number, since it uses as much as digits as its factorization.

2002112011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3411340.

The product of its (nonzero) digits is 8, while the sum is 10.

The square root of 2002112011 is about 44744.9663202466. The cubic root of 2002112011 is about 1260.3643883949.

Adding to 2002112011 its reverse (1102112002), we get a palindrome (3104224013).

Subtracting from 2002112011 its reverse (1102112002), we obtain a palindrome (900000009).

The spelling of 2002112011 in words is "two billion, two million, one hundred twelve thousand, eleven".

Divisors: 1 587 3410753 2002112011