2002101113 has 4 divisors (see below), whose sum is σ = 2048661648. Its totient is φ = 1955540580.

The previous prime is 2002101107. The next prime is 2002101119. The reversal of 2002101113 is 3111012002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (2002101107) and next prime (2002101119).

It is a cyclic number.

It is not a de Polignac number, because 2002101113 - 2⁸ = 2002100857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002101094 and 2002101103.

It is not an unprimeable number, because it can be changed into a prime (2002101119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23280203 + ... + 23280288.

It is an arithmetic number, because the mean of its divisors is an integer number (512165412).

Almost surely, 2^2002101113 is an apocalyptic number.

It is an amenable number.

2002101113 is a deficient number, since it is larger than the sum of its proper divisors (46560535).

2002101113 is an equidigital number, since it uses as much as digits as its factorization.

2002101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46560534.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2002101113 is about 44744.8445410195. The cubic root of 2002101113 is about 1260.3621015638.

Adding to 2002101113 its reverse (3111012002), we get a palindrome (5113113115).

The spelling of 2002101113 in words is "two billion, two million, one hundred one thousand, one hundred thirteen".