Base | Representation |
---|---|
bin | 111011101011010… |
… | …0011100010001101 |
3 | 12011112212112100121 |
4 | 1313112203202031 |
5 | 13100103321141 |
6 | 530410224541 |
7 | 100423063006 |
oct | 16726434215 |
9 | 5145775317 |
10 | 2002401421 |
11 | 938337909 |
12 | 47a725151 |
13 | 25bb08417 |
14 | 14dd221ad |
15 | babd91d1 |
hex | 775a388d |
2002401421 has 2 divisors, whose sum is σ = 2002401422. Its totient is φ = 2002401420.
The previous prime is 2002401391. The next prime is 2002401437. The reversal of 2002401421 is 1241042002.
It is an a-pointer prime, because the next prime (2002401437) can be obtained adding 2002401421 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1981140100 + 21261321 = 44510^2 + 4611^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002401421 - 215 = 2002368653 is a prime.
It is a super-2 number, since 2×20024014212 = 8019222901645638482, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2002401395 and 2002401404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002401451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001200710 + 1001200711.
It is an arithmetic number, because the mean of its divisors is an integer number (1001200711).
Almost surely, 22002401421 is an apocalyptic number.
It is an amenable number.
2002401421 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002401421 is an equidigital number, since it uses as much as digits as its factorization.
2002401421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 128, while the sum is 16.
The square root of 2002401421 is about 44748.2001984437. The cubic root of 2002401421 is about 1260.4251150145.
Adding to 2002401421 its reverse (1241042002), we get a palindrome (3243443423).
The spelling of 2002401421 in words is "two billion, two million, four hundred one thousand, four hundred twenty-one".
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