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2001341345 = 5199722239
BaseRepresentation
bin111011101001010…
…0000101110100001
312011110212200012112
41313102200232201
513044320410340
6530331405105
7100411056263
oct16722405641
95143780175
102001341345
11937783413
1247a2b3795
1325b826a63
1414db27b33
15baa7a065
hex774a0ba1

2001341345 has 24 divisors (see below), whose sum is σ = 2555481600. Its totient is φ = 1500498432.

The previous prime is 2001341341. The next prime is 2001341351. The reversal of 2001341345 is 5431431002.

It is not a de Polignac number, because 2001341345 - 22 = 2001341341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2001341345.

It is not an unprimeable number, because it can be changed into a prime (2001341341) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 892736 + ... + 894974.

It is an arithmetic number, because the mean of its divisors is an integer number (106478400).

Almost surely, 22001341345 is an apocalyptic number.

It is an amenable number.

2001341345 is a deficient number, since it is larger than the sum of its proper divisors (554140255).

2001341345 is an equidigital number, since it uses as much as digits as its factorization.

2001341345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2457 (or 2360 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 2001341345 is about 44736.3537293776. The cubic root of 2001341345 is about 1260.2026517502.

Adding to 2001341345 its reverse (5431431002), we get a palindrome (7432772347).

The spelling of 2001341345 in words is "two billion, one million, three hundred forty-one thousand, three hundred forty-five".

Divisors: 1 5 19 95 97 485 1843 2239 9215 9409 11195 42541 47045 178771 212705 217183 893855 1085915 4126477 20632385 21066751 105333755 400268269 2001341345