2001414031 has 2 divisors, whose sum is σ = 2001414032. Its totient is φ = 2001414030.

The previous prime is 2001414013. The next prime is 2001414047. The reversal of 2001414031 is 1304141002.

Together with previous prime (2001414013) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (2001414047) can be obtained adding 2001414031 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2001414031 - 2⁷ = 2001413903 is a prime.

It is a super-2 number, since 2×2001414031² = 8011316246967337922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2001413996 and 2001414014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001417031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000707015 + 1000707016.

It is an arithmetic number, because the mean of its divisors is an integer number (1000707016).

Almost surely, 2^2001414031 is an apocalyptic number.

2001414031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001414031 is an equidigital number, since it uses as much as digits as its factorization.

2001414031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 2001414031 is about 44737.1661038113. The cubic root of 2001414031 is about 1260.2179078485.

Adding to 2001414031 its reverse (1304141002), we get a palindrome (3305555033).

The spelling of 2001414031 in words is "two billion, one million, four hundred fourteen thousand, thirty-one".