[go: up one dir, main page]

Search a number
-
+
20001403 = 10721747
BaseRepresentation
bin100110001001…
…1001001111011
31101122011202201
41030103021323
520110021103
61552411031
7332003062
oct114231173
941564681
1020001403
1110321394
126846a77
1341b3c66
1429291d9
151b5151d
hex131327b

20001403 has 6 divisors (see below), whose sum is σ = 20201636. Its totient is φ = 19803132.

The previous prime is 20001389. The next prime is 20001439. The reversal of 20001403 is 30410002.

It is a de Polignac number, because none of the positive numbers 2k-20001403 is a prime.

It is a super-2 number, since 2×200014032 = 800112243936818, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20001403.

It is not an unprimeable number, because it can be changed into a prime (20001203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 10576 + ... + 12322.

Almost surely, 220001403 is an apocalyptic number.

20001403 is a deficient number, since it is larger than the sum of its proper divisors (200233).

20001403 is an equidigital number, since it uses as much as digits as its factorization.

20001403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1961 (or 1854 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 10.

The square root of 20001403 is about 4472.2928124174. The cubic root of 20001403 is about 271.4481087243.

Adding to 20001403 its reverse (30410002), we get a palindrome (50411405).

It can be divided in two parts, 2000 and 1403, that added together give a triangular number (3403 = T82).

The spelling of 20001403 in words is "twenty million, one thousand, four hundred three".

Divisors: 1 107 1747 11449 186929 20001403