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20000335 = 54000067
BaseRepresentation
bin100110001001…
…0111001001111
31101122010022011
41030102321033
520110002320
61552402051
7332000005
oct114227117
941563264
1020000335
1110320603
126846327
1341b3624
142928a75
151b5105a
hex1312e4f

20000335 has 4 divisors (see below), whose sum is σ = 24000408. Its totient is φ = 16000264.

The previous prime is 20000329. The next prime is 20000339. The reversal of 20000335 is 53300002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20000335 - 23 = 20000327 is a prime.

It is a super-2 number, since 2×200003352 = 800026800224450, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20000339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000029 + ... + 2000038.

It is an arithmetic number, because the mean of its divisors is an integer number (6000102).

Almost surely, 220000335 is an apocalyptic number.

20000335 is a deficient number, since it is larger than the sum of its proper divisors (4000073).

20000335 is an equidigital number, since it uses as much as digits as its factorization.

20000335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4000072.

The product of its (nonzero) digits is 90, while the sum is 13.

The square root of 20000335 is about 4472.1734089814. The cubic root of 20000335 is about 271.4432772009.

Adding to 20000335 its reverse (53300002), we get a palindrome (73300337).

The spelling of 20000335 in words is "twenty million, three hundred thirty-five", and thus it is an aban number.

Divisors: 1 5 4000067 20000335