Base | Representation |
---|---|
bin | 111011100111100… |
… | …0011010000110111 |
3 | 12011102011120212201 |
4 | 1313033003100313 |
5 | 13044102343411 |
6 | 530300125331 |
7 | 100400260525 |
oct | 16717032067 |
9 | 5142146781 |
10 | 2000434231 |
11 | 937213934 |
12 | 479b36847 |
13 | 25b599bc3 |
14 | 14d96d315 |
15 | ba94b3c1 |
hex | 773c3437 |
2000434231 has 2 divisors, whose sum is σ = 2000434232. Its totient is φ = 2000434230.
The previous prime is 2000434213. The next prime is 2000434273. The reversal of 2000434231 is 1324340002.
Together with previous prime (2000434213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2000434231 - 29 = 2000433719 is a prime.
It is a super-2 number, since 2×20004342312 = 8003474225113122722, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2000434199 and 2000434208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2000434291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000217115 + 1000217116.
It is an arithmetic number, because the mean of its divisors is an integer number (1000217116).
Almost surely, 22000434231 is an apocalyptic number.
2000434231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000434231 is an equidigital number, since it uses as much as digits as its factorization.
2000434231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 19.
The square root of 2000434231 is about 44726.2141366783. The cubic root of 2000434231 is about 1260.0122260928.
Adding to 2000434231 its reverse (1324340002), we get a palindrome (3324774233).
The spelling of 2000434231 in words is "two billion, four hundred thirty-four thousand, two hundred thirty-one".
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