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295335 = 3256563
BaseRepresentation
bin1001000000110100111
3120000010100
41020012213
533422320
610155143
72340015
oct1100647
9500110
10295335
11191987
12122ab3
13a4571
14798b5
155c790
hex481a7

295335 has 12 divisors (see below), whose sum is σ = 511992. Its totient is φ = 157488.

The previous prime is 295333. The next prime is 295357. The reversal of 295335 is 533592.

It is not a de Polignac number, because 295335 - 21 = 295333 is a prime.

It is an Ulam number.

It is a d-powerful number, because it can be written as 215 + 93 + 38 + 5 + 311 + 57 .

It is a junction number, because it is equal to n+sod(n) for n = 295299 and 295308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (295333) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3237 + ... + 3326.

It is an arithmetic number, because the mean of its divisors is an integer number (42666).

295335 is a Friedman number, since it can be written as 5*(9^5+3*3*2), using all its digits and the basic arithmetic operations.

2295335 is an apocalyptic number.

295335 is a deficient number, since it is larger than the sum of its proper divisors (216657).

295335 is a wasteful number, since it uses less digits than its factorization.

295335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6574 (or 6571 counting only the distinct ones).

The product of its digits is 4050, while the sum is 27.

The square root of 295335 is about 543.4473295546. The cubic root of 295335 is about 66.5944913335.

It can be divided in two parts, 295 and 335, that added together give a triangular number (630 = T35).

The spelling of 295335 in words is "two hundred ninety-five thousand, three hundred thirty-five".

Divisors: 1 3 5 9 15 45 6563 19689 32815 59067 98445 295335