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2631113 = 6143133
BaseRepresentation
bin1010000010010111001001
311221200012122
422002113021
51133143423
6132221025
731235612
oct12022711
94850178
102631113
111537881
12a6a775
13711794
144c6c09
1536e8c8
hex2825c9

2631113 has 4 divisors (see below), whose sum is σ = 2674308. Its totient is φ = 2587920.

The previous prime is 2631103. The next prime is 2631133. The reversal of 2631113 is 3111362.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 284089 + 2347024 = 533^2 + 1532^2 .

It is a cyclic number.

It is not a de Polignac number, because 2631113 - 26 = 2631049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2631091 and 2631100.

It is not an unprimeable number, because it can be changed into a prime (2631103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21506 + ... + 21627.

It is an arithmetic number, because the mean of its divisors is an integer number (668577).

22631113 is an apocalyptic number.

It is an amenable number.

2631113 is a deficient number, since it is larger than the sum of its proper divisors (43195).

2631113 is an equidigital number, since it uses as much as digits as its factorization.

2631113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43194.

The product of its digits is 108, while the sum is 17.

The square root of 2631113 is about 1622.0705903258. The cubic root of 2631113 is about 138.0532070962.

Adding to 2631113 its reverse (3111362), we get a palindrome (5742475).

Subtracting 2631113 from its reverse (3111362), we obtain a square (480249 = 6932).

It can be divided in two parts, 2631 and 113, that added together give a cube (2744 = 143).

The spelling of 2631113 in words is "two million, six hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 61 43133 2631113