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2555115593 is a prime number
BaseRepresentation
bin1001100001001011…
…1111100001001001
320121001220022122212
42120102333201021
520213102144333
61101312554505
7120214060412
oct23022774111
96531808585
102555115593
1110a1329188
125b3852a35
13319489124
141a34ba809
15ee4b6448
hex984bf849

2555115593 has 2 divisors, whose sum is σ = 2555115594. Its totient is φ = 2555115592.

The previous prime is 2555115547. The next prime is 2555115643. The reversal of 2555115593 is 3955115552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2365557769 + 189557824 = 48637^2 + 13768^2 .

It is a cyclic number.

It is not a de Polignac number, because 2555115593 - 230 = 1481373769 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2555115593.

It is not a weakly prime, because it can be changed into another prime (2555115503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277557796 + 1277557797.

It is an arithmetic number, because the mean of its divisors is an integer number (1277557797).

Almost surely, 22555115593 is an apocalyptic number.

It is an amenable number.

2555115593 is a deficient number, since it is larger than the sum of its proper divisors (1).

2555115593 is an equidigital number, since it uses as much as digits as its factorization.

2555115593 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 168750, while the sum is 41.

The square root of 2555115593 is about 50548.1512322657. The cubic root of 2555115593 is about 1367.1101806692.

Subtracting from 2555115593 its sum of digits (41), we obtain a palindrome (2555115552).

The spelling of 2555115593 in words is "two billion, five hundred fifty-five million, one hundred fifteen thousand, five hundred ninety-three".