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2551133131 is a prime number
BaseRepresentation
bin1001100000001111…
…0011001111001011
320120210101222202021
42120003303033023
520211042230011
61101051345311
7120135162631
oct23003631713
96523358667
102551133131
11109a059098
125b2452237
133186c3541
141a2b61351
15ede7b471
hex980f33cb

2551133131 has 2 divisors, whose sum is σ = 2551133132. Its totient is φ = 2551133130.

The previous prime is 2551133129. The next prime is 2551133141. The reversal of 2551133131 is 1313311552.

2551133131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2551133131 - 21 = 2551133129 is a prime.

It is a super-2 number, since 2×25511331312 = 13016560504171726322, which contains 22 as substring.

Together with 2551133129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2551133096 and 2551133105.

It is not a weakly prime, because it can be changed into another prime (2551133141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275566565 + 1275566566.

It is an arithmetic number, because the mean of its divisors is an integer number (1275566566).

Almost surely, 22551133131 is an apocalyptic number.

2551133131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2551133131 is an equidigital number, since it uses as much as digits as its factorization.

2551133131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1350, while the sum is 25.

The square root of 2551133131 is about 50508.7431144351. The cubic root of 2551133131 is about 1366.3995415323.

Adding to 2551133131 its reverse (1313311552), we get a palindrome (3864444683).

The spelling of 2551133131 in words is "two billion, five hundred fifty-one million, one hundred thirty-three thousand, one hundred thirty-one".