[go: up one dir, main page]

Search a number
-
+
255011113 = 743847213
BaseRepresentation
bin11110011001100…
…10100100101001
3122202211220111001
433030302210221
51010240323423
641145435001
76214362430
oct1714624451
9582756431
10255011113
11120a46695
127149ba61
1340aa8566
1425c22117
15175c3cad
hexf332929

255011113 has 8 divisors (see below), whose sum is σ = 298219328. Its totient is φ = 213497424.

The previous prime is 255011111. The next prime is 255011117. The reversal of 255011113 is 311110552.

255011113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 255011113 - 21 = 255011111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255011111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 423306 + ... + 423907.

It is an arithmetic number, because the mean of its divisors is an integer number (37277416).

Almost surely, 2255011113 is an apocalyptic number.

It is an amenable number.

255011113 is a deficient number, since it is larger than the sum of its proper divisors (43208215).

255011113 is an equidigital number, since it uses as much as digits as its factorization.

255011113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 847263.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 255011113 is about 15969.0673804077. The cubic root of 255011113 is about 634.1417823201.

Adding to 255011113 its reverse (311110552), we get a palindrome (566121665).

The spelling of 255011113 in words is "two hundred fifty-five million, eleven thousand, one hundred thirteen".

Divisors: 1 7 43 301 847213 5930491 36430159 255011113