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25497643 is a prime number
BaseRepresentation
bin110000101000…
…1000000101011
31202222102012011
41201101000223
523011411033
62310300351
7426504103
oct141210053
952872164
1025497643
1113435836
1286576b7
135389882
14355a203
152389ccd
hex185102b

25497643 has 2 divisors, whose sum is σ = 25497644. Its totient is φ = 25497642.

The previous prime is 25497599. The next prime is 25497653. The reversal of 25497643 is 34679452.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25497643 is a prime.

It is a plaindrome in base 15.

It is a junction number, because it is equal to n+sod(n) for n = 25497596 and 25497605.

It is not a weakly prime, because it can be changed into another prime (25497653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12748821 + 12748822.

It is an arithmetic number, because the mean of its divisors is an integer number (12748822).

Almost surely, 225497643 is an apocalyptic number.

25497643 is a deficient number, since it is larger than the sum of its proper divisors (1).

25497643 is an equidigital number, since it uses as much as digits as its factorization.

25497643 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 181440, while the sum is 40.

The square root of 25497643 is about 5049.5190860121. The cubic root of 25497643 is about 294.3291968681.

The spelling of 25497643 in words is "twenty-five million, four hundred ninety-seven thousand, six hundred forty-three".