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2520122135 = 5504024427
BaseRepresentation
bin1001011000110110…
…0000001100010111
320111122001110122212
42112031200030113
520130122402020
61054022544035
7116310453566
oct22615401427
96448043585
102520122135
1110835a8073
125a3b9801b
1331215633b
1419c9abbdd
15eb3a2cc5
hex96360317

2520122135 has 4 divisors (see below), whose sum is σ = 3024146568. Its totient is φ = 2016097704.

The previous prime is 2520122119. The next prime is 2520122147. The reversal of 2520122135 is 5312210252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2520122135 - 24 = 2520122119 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2520122135.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252012209 + ... + 252012218.

It is an arithmetic number, because the mean of its divisors is an integer number (756036642).

Almost surely, 22520122135 is an apocalyptic number.

2520122135 is a deficient number, since it is larger than the sum of its proper divisors (504024433).

2520122135 is an equidigital number, since it uses as much as digits as its factorization.

2520122135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 504024432.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 2520122135 is about 50200.8180710235. The cubic root of 2520122135 is about 1360.8404074331.

Adding to 2520122135 its reverse (5312210252), we get a palindrome (7832332387).

The spelling of 2520122135 in words is "two billion, five hundred twenty million, one hundred twenty-two thousand, one hundred thirty-five".

Divisors: 1 5 504024427 2520122135