Base | Representation |
---|---|
bin | 110100101111… |
… | …010010101001 |
3 | 222000101121012 |
4 | 310233102221 |
5 | 12014401233 |
6 | 1212153305 |
7 | 225340454 |
oct | 64572251 |
9 | 28011535 |
10 | 13825193 |
11 | 7893088 |
12 | 4768835 |
13 | 2b309b5 |
14 | 1b9c49b |
15 | 1331548 |
hex | d2f4a9 |
13825193 has 2 divisors, whose sum is σ = 13825194. Its totient is φ = 13825192.
The previous prime is 13825177. The next prime is 13825213. The reversal of 13825193 is 39152831.
13825193 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11505664 + 2319529 = 3392^2 + 1523^2 .
It is a cyclic number.
It is not a de Polignac number, because 13825193 - 24 = 13825177 is a prime.
It is a super-2 number, since 2×138251932 = 382271922974498, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13825993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6912596 + 6912597.
It is an arithmetic number, because the mean of its divisors is an integer number (6912597).
Almost surely, 213825193 is an apocalyptic number.
It is an amenable number.
13825193 is a deficient number, since it is larger than the sum of its proper divisors (1).
13825193 is an equidigital number, since it uses as much as digits as its factorization.
13825193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6480, while the sum is 32.
The square root of 13825193 is about 3718.2244418539. The cubic root of 13825193 is about 240.0069037366.
The spelling of 13825193 in words is "thirteen million, eight hundred twenty-five thousand, one hundred ninety-three".
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