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13704433 is a prime number
BaseRepresentation
bin110100010001…
…110011110001
3221210020221121
4310101303301
512002020213
61205422241
7224325421
oct64216361
927706847
1013704433
117810386
12470a981
132abaa42
141b6a481
15130a88d
hexd11cf1

13704433 has 2 divisors, whose sum is σ = 13704434. Its totient is φ = 13704432.

The previous prime is 13704421. The next prime is 13704437. The reversal of 13704433 is 33440731.

It is a happy number.

13704433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7711729 + 5992704 = 2777^2 + 2448^2 .

It is an emirp because it is prime and its reverse (33440731) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13704433 is a prime.

It is a super-2 number, since 2×137044332 = 375622967702978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13704398 and 13704407.

It is not a weakly prime, because it can be changed into another prime (13704437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6852216 + 6852217.

It is an arithmetic number, because the mean of its divisors is an integer number (6852217).

Almost surely, 213704433 is an apocalyptic number.

It is an amenable number.

13704433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13704433 is an equidigital number, since it uses as much as digits as its factorization.

13704433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 25.

The square root of 13704433 is about 3701.9498916112. The cubic root of 13704433 is about 239.3060567882.

The spelling of 13704433 in words is "thirteen million, seven hundred four thousand, four hundred thirty-three".