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1359408983 is a prime number
BaseRepresentation
bin101000100000110…
…1110111101010111
310111201222010112212
41101001232331113
510241002041413
6342520504035
745454533332
oct12101567527
93451863485
101359408983
116383950a9
1231b31b01b
13188838c1a
14cc787619
157e527ca8
hex5106ef57

1359408983 has 2 divisors, whose sum is σ = 1359408984. Its totient is φ = 1359408982.

The previous prime is 1359408929. The next prime is 1359408989. The reversal of 1359408983 is 3898049531.

It is a strong prime.

It is an emirp because it is prime and its reverse (3898049531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1359408983 - 218 = 1359146839 is a prime.

It is a super-2 number, since 2×13594089832 = 3695985566122188578, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1359408989) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 679704491 + 679704492.

It is an arithmetic number, because the mean of its divisors is an integer number (679704492).

Almost surely, 21359408983 is an apocalyptic number.

1359408983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1359408983 is an equidigital number, since it uses as much as digits as its factorization.

1359408983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 933120, while the sum is 50.

The square root of 1359408983 is about 36870.1638591423. The cubic root of 1359408983 is about 1107.7711363222.

The spelling of 1359408983 in words is "one billion, three hundred fifty-nine million, four hundred eight thousand, nine hundred eighty-three".