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1355240473 is a prime number
BaseRepresentation
bin101000011000111…
…0101010000011001
310111110010100102121
41100301311100121
510233420143343
6342251301241
745404232256
oct12061652031
93443110377
101355240473
11635aa8254
12319a4a821
13187a09752
14cbdc042d
157dea2aed
hex50c75419

1355240473 has 2 divisors, whose sum is σ = 1355240474. Its totient is φ = 1355240472.

The previous prime is 1355240407. The next prime is 1355240479. The reversal of 1355240473 is 3740425531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 687121369 + 668119104 = 26213^2 + 25848^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355240473 - 229 = 818369561 is a prime.

It is not a weakly prime, because it can be changed into another prime (1355240479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677620236 + 677620237.

It is an arithmetic number, because the mean of its divisors is an integer number (677620237).

Almost surely, 21355240473 is an apocalyptic number.

It is an amenable number.

1355240473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355240473 is an equidigital number, since it uses as much as digits as its factorization.

1355240473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 34.

The square root of 1355240473 is about 36813.5908734804. The cubic root of 1355240473 is about 1106.6376822117.

The spelling of 1355240473 in words is "one billion, three hundred fifty-five million, two hundred forty thousand, four hundred seventy-three".