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135401471 is a prime number
BaseRepresentation
bin10000001001000…
…00111111111111
3100102210002220022
420010200333333
5234130321341
621234042355
73232615322
oct1004407777
9312702808
10135401471
116a481147
12394193bb
132208a21a
1413da87b9
15bd48e4b
hex8120fff

135401471 has 2 divisors, whose sum is σ = 135401472. Its totient is φ = 135401470.

The previous prime is 135401423. The next prime is 135401477. The reversal of 135401471 is 174104531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135401471 - 214 = 135385087 is a prime.

It is a super-3 number, since 3×1354014713 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135401471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135401477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67700735 + 67700736.

It is an arithmetic number, because the mean of its divisors is an integer number (67700736).

Almost surely, 2135401471 is an apocalyptic number.

135401471 is a deficient number, since it is larger than the sum of its proper divisors (1).

135401471 is an equidigital number, since it uses as much as digits as its factorization.

135401471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1680, while the sum is 26.

The square root of 135401471 is about 11636.2137742480. The cubic root of 135401471 is about 513.5008035227.

The spelling of 135401471 in words is "one hundred thirty-five million, four hundred one thousand, four hundred seventy-one".