Base | Representation |
---|---|
bin | 101000010111010… |
… | …1000011011001001 |
3 | 10111101112201112211 |
4 | 1100232220123021 |
5 | 10233211321411 |
6 | 342221305121 |
7 | 45364136236 |
oct | 12056503311 |
9 | 3441481484 |
10 | 1354401481 |
11 | 635584974 |
12 | 3197051a1 |
13 | 1877a48c4 |
14 | cbc4278d |
15 | 7dd89221 |
hex | 50ba86c9 |
1354401481 has 2 divisors, whose sum is σ = 1354401482. Its totient is φ = 1354401480.
The previous prime is 1354401403. The next prime is 1354401527. The reversal of 1354401481 is 1841044531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1317690000 + 36711481 = 36300^2 + 6059^2 .
It is an emirp because it is prime and its reverse (1841044531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1354401481 - 27 = 1354401353 is a prime.
It is a super-2 number, since 2×13544014812 = 3668806743469986722, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1354404481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677200740 + 677200741.
It is an arithmetic number, because the mean of its divisors is an integer number (677200741).
Almost surely, 21354401481 is an apocalyptic number.
It is an amenable number.
1354401481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354401481 is an equidigital number, since it uses as much as digits as its factorization.
1354401481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
The square root of 1354401481 is about 36802.1939699252. The cubic root of 1354401481 is about 1106.4092721149.
The spelling of 1354401481 in words is "one billion, three hundred fifty-four million, four hundred one thousand, four hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.000 sec. • engine limits •