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135325433 is a prime number
BaseRepresentation
bin10000001000011…
…10011011111001
3100102122020121002
420010032123321
5234120403213
621232254345
73232150535
oct1004163371
9312566532
10135325433
116a42a001
12393a13b5
1322061729
1413d88bc5
15bd31658
hex810e6f9

135325433 has 2 divisors, whose sum is σ = 135325434. Its totient is φ = 135325432.

The previous prime is 135325387. The next prime is 135325451. The reversal of 135325433 is 334523531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82210489 + 53114944 = 9067^2 + 7288^2 .

It is a cyclic number.

It is not a de Polignac number, because 135325433 - 214 = 135309049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135325396 and 135325405.

It is not a weakly prime, because it can be changed into another prime (135325453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67662716 + 67662717.

It is an arithmetic number, because the mean of its divisors is an integer number (67662717).

Almost surely, 2135325433 is an apocalyptic number.

It is an amenable number.

135325433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135325433 is an equidigital number, since it uses as much as digits as its factorization.

135325433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16200, while the sum is 29.

The square root of 135325433 is about 11632.9460155199. The cubic root of 135325433 is about 513.4046625549.

Adding to 135325433 its reverse (334523531), we get a palindrome (469848964).

It can be divided in two parts, 135325 and 433, that multiplied together give a triangular number (58595725 = T10825).

The spelling of 135325433 in words is "one hundred thirty-five million, three hundred twenty-five thousand, four hundred thirty-three".